-4.9t^2+34.3t=0

Solution for -4.9t^2+34.3t=0 equation:

-4.9t^2+34.3t=0

a = -4.9; b = 34.3; c = 0;
Δ = b2-4ac
Δ = 34.32-4·(-4.9)·0
Δ = 1176.49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34.3)-\sqrt{1176.49}}{2*-4.9}=\frac{-34.3-\sqrt{1176.49}}{-9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34.3)+\sqrt{1176.49}}{2*-4.9}=\frac{-34.3+\sqrt{1176.49}}{-9.8}
$